The following identities ought to hold (for some value of =):
return x >>= f = f x
t >>= fun x -> return x = t
(t >>= f) >>= g = t >>= fun x -> (f x >>= g)
Note: >>=
is the infix notation for bind
)
The map
argument to Monad.Make
says how to implement the monad's map
function.
`Define_using_bind
means to define map t ~f = bind t (fun a -> return (f a))
.
`Custom
overrides the default implementation, presumably with something more
efficient.
Some other functions returned by Monad.Make
are defined in terms of map
, so
passing in a more efficient map
will improve their efficiency as well.