module Hashable:
Hashable
and Hashable_t
functors is that the former's
result type doesn't contain type t
and the latter does. Therefore, Hashable
can't
be used to combine two pairs into 4-tuple. but Hashable_t
can. On the other hand
result of Hashable_t
cannot be combined with Comparable
.
example: module Four_ints = Tuple.Hashable_t (Tuple.Hashable_t (Int)(Int)) (Tuple.Hashable_t (Int)(Int))
If instead we used Hashable
compiler would complain that the input to outer functor
doesn't have type t
.
On the other hand: module Foo = struct type t = String.t * Int.t include Tuple.Comparable (String.t) (Int) include Tuple.Hashable (String.t) (Int) end
If we used Hashable_t
above, compiler would compile that we have two types t
defined.
Unfortunately, it is not possible to define just one functor that could be used in
both cases.
Parameters: |
|
type
t
include Hashable.S
val t_of_sexp : Sexplib.Sexp.t -> t
val sexp_of_t : t -> Sexplib.Sexp.t